Passing arrays to functions in C are by reference

The following code illustrates this;

#include <stdio.h>

void test(char d[])

{

// Print the value passed to the function.

printf("VALUE IN FUNCTION - DATA: %d\n",d[2]);

d[2]=9; // We'll change the value.

}

void test2(int a)

{

// Print the value passed to the function.

printf("VALUE IN FUNCTION - INT: %d\n",a);

a=99; // We'll change the value.

}

int main()

{

// Setup the values

char DATA[5]={1,2,3,4,5};

int b=10;

printf("\n");

printf("BEFORE FUNCTION CALLS - DATA: %d INT: %d\n",DATA[2],b);

test(DATA);

test2(b);

// Print the values after the functions.

printf("AFTER FUNCTION CALLS - DATA: %d INT: %d\n",DATA[2],b);

}